j^2-18j+50=-3j

Solution for j^2-18j+50=-3j equation:

Simplifying
j2 + -18j + 50 = -3j

Reorder the terms:
50 + -18j + j2 = -3j

Solving
50 + -18j + j2 = -3j

Solving for variable 'j'.

Reorder the terms:
50 + -18j + 3j + j2 = -3j + 3j

Combine like terms: -18j + 3j = -15j
50 + -15j + j2 = -3j + 3j

Combine like terms: -3j + 3j = 0
50 + -15j + j2 = 0

Factor a trinomial.
(5 + -1j)(10 + -1j) = 0

Subproblem 1
Set the factor '(5 + -1j)' equal to zero and attempt to solve:

Simplifying
5 + -1j = 0

Solving
5 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1j = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1j = 0 + -5
-1j = 0 + -5

Combine like terms: 0 + -5 = -5
-1j = -5

Divide each side by '-1'.
j = 5

Simplifying
j = 5
Subproblem 2
Set the factor '(10 + -1j)' equal to zero and attempt to solve:

Simplifying
10 + -1j = 0

Solving
10 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1j = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1j = 0 + -10
-1j = 0 + -10

Combine like terms: 0 + -10 = -10
-1j = -10

Divide each side by '-1'.
j = 10

Simplifying
j = 10
Solution
j = {5, 10}